np.random.rand(len(df)) returns an array of uniform random numbers between 0 and 1, np.random.rand(len(df)) < 0.8 will transform it into an ... ... <看更多>

I think I see what you mean, that you are would like a call to a Numba implementation of e.g. np.random.rand() to a) sync from NumPy's RNG ... ... <看更多>

Generally, for an array with random values in the range [a,b] you have (b-a)*np.random.random(())+a.This ... ... <看更多>