ddtθ=˙θ. So what you are asking is basically d2dt2θ2. First, ddtθ2=˙θ2=2θ˙θ. Second, ddt(˙θ2)=ddt(2θ˙θ)=2˙θ2+2θ¨θ. ... <看更多>

I want to write theta dot in sympy using the expression below but sympy outputs peculiar result sp.symbols("\dot{\theta}") (, ℎeta˙) i ... ... <看更多>

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The sigmoid function has been used to evaluate the probability of the dot product of the weights (theta) and feature vector(NumPy array of ... ... <看更多>